Two full 48-gallon tanks begin draining at t = 0. Tank Alpha's volume is changing
at a constant rate of -16/5 gal/min. The rate at which Tank Bravo's volume is
changing is given by r(t)=-1/3t-1 gal/min.

a) How much water is in each tank after 5 minutes?
b) Which tub drains rst? How do you know?

Hint: The water in tank alpha is wa(t) = 48 - (16/5)t
t/
The water in tank bravo is wb(t) = 48 + | (-(t/3) -1) dt.
0/

I assume that tank bravo drains at rate r(t) = (-(t/3) - 1) and not
r(t) = -(1/3t) -1 or r(t) = -1/(3t - 1), otherwise, the integral would diverge.