1. A billiard ball moving at a speed of 2.2 m/s strikes an identical stationary ball a glancing blow.After the collision,one ball is found to be moving at a speed of 1.1 m/s in a direction making a 60° angle with the original line of motion.i) Find the velocity of other ball.ii) Can the collision be inelastic,given these data? Justify your answer.

Hint: Use the law of conservation of momentum.

m1v*1 + m2v*2 before = m1v*1 + m2v*2 after.

Here, v* denotes the velocity vector, and v denotes the speed.

In an elastic collision, kinetic energy is conserved. i.e.

(m1v1^2)/2 + (m2v2^2)/2 before = (m1v1^2)/2 + (m2v2^2)/2 after.

In an inelastic collision, the total kinetic energy after is less than
the total kinetic energy after.

In a completely inelastic collision, the balls would stick together afterwards.

In an inelastic collision, the total kinetic energy after is less than the total kinetic energy before the collision. My bad. Hope this helps.
-CWH :-)