cot(x) + tan(x)
1-tan(x) 1-cot(x) = 1+tan(x)+cot(x)



Please verify if you can!!

There are always many methods to tackle these critters, but I will do a somewhat lengthy one so you can see the identities. OK?



Like any addition, you must make the denominators the same:

Let's multiply the right side by -tan(x):



Now you have:





Using :

We simplify it down to:



Since



So, we're getting there:





Now,

Therefore, we have... drum roll please:




This is a rather lengthy derivation but if you can follow it, you can follow amore simplistic method.

I appreciate the reply but I still am confused by some of your answer. First I don't see how you derived the new equation when you put it all in terms of sin and cos. Then I don't see how 1/sin(x)cos(x)can be equal to cot(x)+tan(x). If you could elaborate more I would appreciate it.

That's how you do these things a lot of the time is by converting to sine and cosine.

You must know variuos identities in order to transform the left side into the right side.




So, we have:



Cross multiply:



Remember,

Therefore:

Quote:

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Originally Posted by adam1231

cot(x) + tan(x)
1-tan(x) 1-cot(x) = 1+tan(x)+cot(x)



Please verify if you can!!!!

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I have no idea

I wish I knew who you were. I have mrs.philips as my precal teacher