A 450 kg car is driving at 60mph. The car hits a patch of ice and hits brakes. If coefficient of friction between tires and ice is 0.07, how far will the car slide before coming to a full stop. And how mechanical energy was taken by friction?
![]() |
A 450 kg car is driving at 60mph. The car hits a patch of ice and hits brakes. If coefficient of friction between tires and ice is 0.07, how far will the car slide before coming to a full stop. And how mechanical energy was taken by friction?
Use equivalence of work and energy. The initial kinetic energy of thecar is:
This energy must be opposed by the work of friction that slows the car to zero. The work done by friction is:
You can calculate F given the car's weight and coefficient of friction. So now you have everything you need to calculate the distance. As for the second part of the question - I've already given you a good hint for that.
All times are GMT -7. The time now is 05:23 AM. |