Ax ^ 2 + bx + c + 0. Where a does not equal 0, may have how many solutions? Explain why?
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Ax ^ 2 + bx + c + 0. Where a does not equal 0, may have how many solutions? Explain why?
ax ^ 2 + bx + c = 0
1- if bē>4ac
There are two solutions.
2- If bē=4ac
There is one solution.
3-if bē<4ac
There are no real solutions (not real numbers)
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