Hari and Faridth have $ 120. Hari and Peter have $ 230. Peter has 6 times as much
Money as Faridth. How much money does Hari have.

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Solve these equations where variables are first letters of their names.

H + F = 120
H + P = 230
P = 6F

Hint: Substitute for P in second equation. Then you have two equations in variables H and F. Try solving them.

consider Hari as H, Faridth as F, Peter as P

As the statement the equation is

H + F = 120 -----------------(1)
H + P = 230 -----------------(2)

given P= 6F

substitute P=6 F in the equation (2)

H + 6 F = 230 ------------------- (3)

Solving equation (1) and (3) subtract equation (1) and (3)

H + F = 120
H + 6 F = 230
--------------------
- 5 F = -110
5 F = 110
i.e F = 22

Sub F in P= 6 F, P= 132

So the value of H is

H + 6(F) = 230
H + 6(22) = 230
H + 132 = 230
therefor, H = 230- 132 = 98, H= 98, So Hari has $ 98.00