What are the roots of this equation?

x2 - 4x + 9 = 0

x2 - 4x + 9 = 0



x2 -4x = -9

x-2x= -4.5

-x=-4.5

x=4.5

It has been a while since I have done algebra, but I think this is the answer.

Quote:

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Originally Posted by 1102568

x2 - 4x + 9 = 0



x2 -4x = -9

x-2x= -4.5

-x=-4.5

x=4.5

It has been a while since I have done algebra, but I think this is the answer.

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I suspect that the OP meant this:



kan_21: use the quadratic formula to solve this. The roots turn out to be complex.

Using the discriminant,

b^2 - 4ac

One will see that the roots are unreal numbers; complex.

You have already been advised to use the quadratic equation here.

x^2 -4x+9 =0
consider the formula, x = [-b ± √(b2 - 4ac)]/2a ------------(1)
standard form of the equation is y=a(x^2)+bx+c
from the equation, a = 1, b = -4, c=9
substitute the values to the equation (1)
consider the formula, x = [-b ± √(b2 - 4ac)]/2a
This will help you in finding x.