How do I find five different rational numbers to represent 12%?



An unfair coin, with P(Heads) = 0.55 is flipped two times. It says draw a tree diagram for this and determine the probability that both flips yield the same result. I drew a tree diagram, but I don't know how to determine the probability. Can you tell me how to do this?



Finally, how do I find the probablity of picking a ten and a club, and picking a two or not a diamond from a deck of 52 cards? Hopefully, you can help me figure out these problems. I am having a hard time doing these.

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How do I find five different rational numbers to represent 12%?

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12% is equal to 3/25. Find 4 more fractions which are equal to 3/25.

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An unfair coin, with P(Heads) = 0.55 is flipped two times. It says draw a tree diagram for this and determine the probability that both flips yield the same result. I drew a tree diagram, but I don't know how to determine the probability. Can you tell me how to do this?

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Start at the trunk of the tree and branch out with H=head and T=tails. If the probablity of getting a head is 0.55, then the probability of getting another head would be? Think multiplication principle.

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Finally, how do I find the probablity of picking a ten and a club, and picking a two or not a diamond from a deck of 52 cards? Hopefully, you can help me figure out these problems. I am having a hard time doing these.

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This problem statement is rather ambiguous. Are you drawing 2 cards with or without replacement? The probability of choosing a ten and a club: Do you mean in two draws without replacement?

The probability of choosing a 2 or NOT a diamond in one draw:

There are 39 non-diamonds in a deck. There are 4 twos.

The probability of choosing a two is 4/52. The proabiltiy of choosing a non-diamond is 39/52. But you must subtract the non-diamonds which are twos because of overcounting.
That would be 3/52.

At least one head on the two flips