(cos3x + sin3x)/(cos3x - sin3x) - (cos3x - sin3x)/(cos3x + sin3x) = 2tan6x
help please. I'm lost. I substitute w for 3x then go from there but I get stuck at 4sinwcosw/(2cos^2w-1)
![]() |
(cos3x + sin3x)/(cos3x - sin3x) - (cos3x - sin3x)/(cos3x + sin3x) = 2tan6x
help please. I'm lost. I substitute w for 3x then go from there but I get stuck at 4sinwcosw/(2cos^2w-1)
2sinwcosw/(cos^2w-sin^2w) is the formula for tan(2w):Quote:
Originally Posted by nohea
tan(2w) = sin(2w)/cos(2w) = 2 sin(w)cos(w)/(2cos(w)-1)
So you're there!
All times are GMT -7. The time now is 09:06 AM. |