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-   -   (cscx+secx)/(sinx+cosx)=cotx+tanx (https://www.askmehelpdesk.com/showthread.php?t=745712)

  • Apr 23, 2013, 06:18 PM
    fenway7890
    (cscx+secx)/(sinx+cosx)=cotx+tanx
    Verify the identity
  • Apr 24, 2013, 07:51 AM
    ebaines
    As usual first step is to convert the tangent, cotangent, secant, and cosecant functions to their sine and cosine equivalents, then simplify. Look for opportunities to use other well-known identities such as cos^2x + sin^2x = 1.

    Show us your progress in this and we can give a hint if you get stuck.

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