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find the vertex & focus of the parabola : (y+1)^2 - 12 (x-2) = 0
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Dec 6, 2012, 04:36 PM
marinebabe00
find the vertex & focus of the parabola : (y+1)^2 - 12 (x-2) = 0
I really need help with this for pre cal please!
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