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  • Mar 13, 2007, 11:18 AM
    emmmay61
    9th Grade Algebra
    Solving for a Specific Variable

    Solve for y:... I need to show my work

    xy = 6

    and

    x - 4y/3 = 8


    HELP
  • Mar 13, 2007, 11:31 AM
    Capuchin
    okay rules for this, you must do to the left side, what you do to the right side.

    So on the first one, you can divide both sides by x, and you get an equation of the form y= which is what you want.

    Now bearing my rule in mind, you work out the answer of the first one (doing what I said), then have a go at the second one.
  • Mar 13, 2007, 11:40 AM
    asterisk_man
    the basic idea is that you need to invert every operation so that you just have y on the left.
    multiplication and division are inverses
    addition and subtraction are inverses
    if you've got one you need to apply the other.

    remember that x-x=0 and x/x=1

    for example:
    solve for y
    2x+y/7=2
    first remove the 2x by subtracting 2x from both sides
    2x+y/7-2x=2-2x
    the 2x and the -2x on the left cancel to be +0 which can be removed since it contributes nothing
    y/7=2-2x
    now remove the 7 by multiplying both sides by 7
    7*y/7=7*(2-2x)
    the 7 and 1/7 combine to be 1 which can be removed because 1*y=y

    so now you've got
    y=7*(2-2x)


    there's one example. Give us what you've gotten so far and we can help you from there.
  • Jun 21, 2008, 04:47 PM
    chancelord
    x-4y/3 = 8 first you start by passing the 3 to the other side multiplying it by 8
    x-4y= 8.3
    x-4y= 24 then, you pass the 4 to the other side by dividing it in 24
    x-y= 24/4
    x-y= 6 now you must subtract x to 6
    -y= 6-x then after this you must divide every ingle term in the equation by -1 that is multiplying by y,
    and you got y= -6+x, which is the final answer
  • Jun 23, 2008, 09:58 AM
    mnjkr123
    Solve for y:... I need to show my work

    xy = 6

    and

    x - 4y/3 = 8


    From xy=6 => x = 6/y

    Substitute the value of x in the 2nd equation

    6/y-4y/3 =8

    Now Multiply by y both on the left and right side

    => 6 - 4 y**2/3 = 8y

    => 4 y**2/3 + 8y - 6 =0

    So, now this is quadratic equation

    Multiply again by 3 both on the left and right side of "=" sign

    => 4 y**2 + 24 y - 18 = 0

    now divide by 2

    => 2 y**2 + 12 y - 9 = 0

    y = (-12 ± sq root (144 + 4*2*9))/2*2

    y = (-12 ± 14.7 ) / 4

    y = 0.675 or -6.675
    =>

    from mnjkr123

    Mathematics Education, Tutoring and Outsourcing
  • Jun 11, 2009, 04:09 PM
    shaebrown
    Xy=6
    and
    x-4y/3=8
    so I divide each sid by x and it left me with y
    x-4y/3=8
    - -
    x x
  • May 3, 2010, 04:44 PM
    andrik
    Quote:

    Originally Posted by Capuchin View Post
    okay rules for this, you must do to the left side, what you do to the right side.

    So on the first one, you can divide both sides by x, and you get an equation of the form y= which is what you want.

    Now bearing my rule in mind, you work out the answer of the first one (doing what i said), then have a go at the second one.

    I am a ninth grader and I need help in algebra
    Can you help me
  • May 3, 2010, 04:46 PM
    andrik

    m=-6/5 and b=-2
  • Jul 19, 2010, 09:31 AM
    amanda.downing96
    :confused:
    Quote:

    Originally Posted by emmmay61 View Post
    Solving for a Specific Variable

    Solve for y: ... I need to show my work

    xy = 6

    and

    x - 4y/3 = 8


    HELP

  • Sep 23, 2010, 06:23 AM
    kristylemere
    This internet site has the answer and help with the steps

    http://www.tutorvista.com/math/solve-this-equation-3x-4y-8
  • Feb 4, 2012, 05:48 PM
    tovian
    y=6/x, 3x/4-24=y
  • Feb 4, 2012, 05:51 PM
    tovian
    solve the above equation step by step for me please

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