Ask Me Help Desk - 6 distinct roots of Complex Number

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6 distinct roots of Complex Number

I am trying to find the z0 to z6 roots of this equation but I am stuck here. Anyone care to show the step by step on how to procced?

$z^{6}-1 = \left [\frac{64j(1-j)}{1+2j} \right ]^{6} \\\ \\\ z^{6}-1 = \left [\frac{64j-64j^{2}}{1+2j} \right ]^{6} \\\ \\\ z^{6}-1 = \left [\frac{64+64j}{1+2j} \right ]^{6} \\\ \\\ z^{6}-1 = \left [\frac{192}{5} -\frac{64j}{5} \right ]^{6}$

Ummmm, the site rules allow ONE question per topic... you have posted THREE so far...

Quote:

Originally Posted by smoothy

Ummmm, the site rules allow ONE question per topic...you have posted THREE so far...

Make that 4!

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