An automobile starts from rest and accelerates to a final velocity in two stages along a straight road. Each stage occupies the same amount of time. In stage 1, the magnitude of the car's acceleration is 3.2 m/s2. The magnitude of the car's velocity at the end of stage 2 is 2.0 times greater than it is at the end of stage 1. Find the magnitude of the acceleration in stage 2.

Have you tried setting up the equations for this? Remember .

a= 3.2 m/s^2
and
t=2.0
a= 3.2(2.0)
is this what I should be doing?

Not quite, The change in velocity in phase 1 is . Since = 0, you have


The change in velocity in phase 2 is and you know that .

Can you take it from here?

Could you give me a walk through of all the steps up to the solution I am still unsure how to go about to solve this question.