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-   -   Trigonometric identities solver (https://www.askmehelpdesk.com/showthread.php?t=684926)

  • Jul 20, 2012, 03:50 AM
    Mon_Troy
    trigonometric identities solver
    I need help in this problems I'm a little confused..
    verify each identity.. show your solution

    1. sinx secx = tanx
    2. tan(-x) cosx = -sinx
    3. tanx cscx cosx = 1
    4. secx - secx sin^2x = cosx
    5. cos^2x-sin^2x= 1-2sin^2x
    6. csc(data)-sin(data)=cot(data)cos(data)
    7. tan(data)cot(data) = Sin(data)
    csc(data)
    8. sin^2(data) (1+cot^2(data))=1
    9. sin(data) tan(data)= 1-cos^2(data)
    cos(data)
    10. csc^2x = cscxsecx
    cotx
    11. tan^2x = secx cosx
    secx
    12. sinx + cosx =1
    cscx secx
    13. Tanx + cosx = secx
    1+sinx
    14. 1- sin^2x = cosx
    1+cosx
    15. cosx + 1-sinx = 2secx
    1-sinx cosx
  • Jul 20, 2012, 04:07 AM
    Unknown008
    Show your attempt please. Thanks.
  • Jul 20, 2012, 06:35 AM
    ebaines
    In general you can solve these by replacing the tan(x), cot(x), sec(x), and csc(x) funtions with their sin(x) and cos(x) equivalents, then doing some algebraic maniipulations and perhaps applying some of the basic trig identities as needed, such as:

    sin^2x + cos^2x = 1
    sin(2x) = 2sinx cosx
    cos(2x) = cos^2x - sin^2x

    For example, the first problem is sin()x sec(x) = tan(x). Replace sec(x) with 1/cos(x) and it comes right out. Now show us your attempts on the remaining ones and we'll help you out if you get stuck.
  • Jul 21, 2012, 12:01 AM
    Mon_Troy
    Quote:

    Originally Posted by ebaines View Post
    In general you can solve these by replacing the tan(x), cot(x), sec(x), and csc(x) funtions with their sin(x) and cos(x) equivalents, then doing some algebraic maniipulations and perhaps applying some of the basic trig identities as needed, such as:

    sin^2x + cos^2x = 1
    sin(2x) = 2sinx cosx
    cos(2x) = cos^2x - sin^2x

    For example, the first problem is sin()x sec(x) = tan(x). Replace sec(x) with 1/cos(x) and it comes right out. Now show us your attempts on the remaining ones and we'll help you out if you get stuck.

    Tnx for the help...

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