a financial report showes that 65% of accountants are employed in the public sector accounting assume that this percentage applies to a group of five college graduates entering the profession what is the probability that at least three graduates will be employeed in public accounting

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Originally Posted by 10072010

a financial report showes that 65% of accountants are employed in the public sector accounting assume that this percentage applies to a group of five college graduates entering the profession what is the probability that at least three graduates will be employeed in public accounting

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The probability that at least three enter the profession equals the probability that exactly three will enter the profession, plus the probability that exactly four will, plus the probability that exactly five will. In general you need to determine the probability that 'k' people out of 'n' total will do something when each individual has a probability of 'p' of doing so, in this case where n=5, p=0.65, and k = 3, 4, or 5. Do you know how to do that?

Can someone help me with this problem thanks. If you have some of employees whom come in different time, during first an hour came 7 person, second an hour came 4 person and last hour came 11 person, now what the probability that of 3 person will com during first an hour.

There are a total of 22 people, 7 of whom came in the first hour. If you pick one person at random from the 22 the probability that he came in that first hour is 7/22 If that pick is successful, then the probability that a second person randomly selected also came in the first hour is 6/21 - the 6 in the numerator is because there are only 6 people left yet unchosen who came in the first hour, out of 21 people left to chose from. Hence the probability that two people chosen at random both came in the first hour is (7/22) x (6/21). Now, think about how to extend this reasoning for a third person. Post back with what you get for an answer and we'll check it for you.

First of all , I would like to thank you for your concerned and I think the probability that three people chosen at random came in the first hour is (7/22) x (6/21) x (5/20)

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Originally Posted by kfaaf

First of all , I would like to thank you for your concerned and I think the probability that three people chosen at random came in the first hour is (7/22) x (6/21) x (5/20)

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Correct!