solve for x, e^x+1=0

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Originally Posted by VICTOR101010101

solve for x, e^x+1=0

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Have you studied d'Moivre's theorem?



where is a real number. Here you need to find a value for such that and .

well, I guess we can Manipulate the equation,
given: e^x+1=o
:- e^x= -1
:- taking log on both sides
:- x = -log 1 ( log and e cancel out)
therefore,
:- x = 0
hope it works, bcoz its just a Hunch!

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Originally Posted by cyber_i9

well, i guess we can Manipulate the equation,
given: e^x+1=o
:- e^x= -1

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You made a mistake there. From e^x+1=0 you get e^x = -1, which leads to x = ln(-1). Hence the need to apply complex numbers.