solve x^2-10x+7=0
what I have so far is this..
x^2-10x____=-7
I don't know what 2 do next!

Are you familiar with the quadratic equation? If , then

yes
so then I plug it in and..
x= -10x -+ squre root of 10x^2-4ax^2+7
over 2(-10)

Not quite. Given x^2-10x + 7=0, the coefficient of the x^2 term is 'a,' so a=1. The coefficient of the x term is 'b,' so b=-10. And the constant at the end is c, so c=7. Plug these values into the quadratic equation to find values for x.

I don't get that!

I'll do a different equation for you as an example. Suppose you want to find values of x that satisfy 2x^2-4x-6=0. In this equation a=2, b=-4, and c=-6. So the quadratic equation becomes:



So the answer is x equals either 3 or -1. To check that this is correct it's a good idea to plug these two values back into the original equation and see if it works:

For x=3:
2(3)^2 -4(3)-6 = 18-12-6 = 0

For x=-1:
2(-1)^2 -4(-1) -6 = 2+4-6 = 0

So these values of x do indeed satisfy the original equation.

You can apply this same process to your problem. Hope this helps.

Yes it does thanks! <3