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  • Jun 13, 2012, 02:21 PM
    qwertyuioop
    Math equations
    2(4c-7)=8c+14
    8c-14-8c+14
    8c-8c-14+14
    = 0
    so the answer is 0?
  • Jun 13, 2012, 02:26 PM
    Curlyben



    Slight mistake in the next part..
    Go slow and steady and do the same on both sides..
    Do ONE step at a time..

    Actually this one doesn't make any sense.
    Are you sure it's correct ?
  • Jun 13, 2012, 02:31 PM
    qwertyuioop
    OK but the abswer is still 0 right ?
    8c-14=8c+14
    because it all croses out so its 0
  • Jun 13, 2012, 02:32 PM
    Curlyben
    Well actually this is how it works out.

    8c-14=8c+14
    8c-14-8c=14
    so
    0c-14=14
    0c-14+14=14+14
    0c=28!

    See the problem here...
  • Jun 13, 2012, 02:35 PM
    qwertyuioop
    I got it but y don't u move the other 14 so it looks like
    8c-14-8c-14?
  • Jun 13, 2012, 02:36 PM
    Curlyben
    Because then you get
    0c-28=0
    so
    0c=28
    as I posted above.

    Now what happens when you divide anything by ZERO ?
  • Jun 13, 2012, 02:38 PM
    Wondergirl
    Did he copy the problem correctly? (I can't stay out of this!)
  • Jun 13, 2012, 02:38 PM
    qwertyuioop
    O I get it now thanks!
  • Jun 13, 2012, 02:38 PM
    Curlyben
    Do you see the problem here?
  • Jun 13, 2012, 02:40 PM
    qwertyuioop
    You
  • Jun 13, 2012, 02:42 PM
    Curlyben
    So what was the mistake ?
  • Jun 13, 2012, 02:43 PM
    qwertyuioop
    It makes the answer 0!
  • Jun 13, 2012, 02:44 PM
    Curlyben
    Noo
    What do you get if you dive any number by ZERO ?

    How many zeros in 1??
  • Jun 13, 2012, 02:48 PM
    qwertyuioop
    hu?
    I just went on a calculator and did 0 divided by 7(random number) and I got 0
  • Jun 13, 2012, 02:50 PM
    Curlyben
    Well that's because the calculator gives up and panics ;)

    There's an infinite number of ZEROs in any given number, so a calculator produces and error state...

    Division by zero - Wikipedia, the free encyclopedia
  • Jun 13, 2012, 02:52 PM
    qwertyuioop
    Oh k got it
  • Jun 13, 2012, 02:53 PM
    Curlyben
    So because of that, there's an error in the original equation.
    Your method is getting there though..
  • Jun 13, 2012, 02:53 PM
    qwertyuioop
    Kk

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