y(x)=4/(1+tan^2x)-3
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y(x)=4/(1+tan^2x)-3
I know to identities this has just thrown me to the deep end
I got it down to y(x)=4cos^2/(1+(1/cos^2x)-3
no one can help?. I put it in wolfram and it gives y(x)=1-4sin^2(x)
any help on how to get to there
yeah my mistake was when I multiply sin^2x/cos^2x by cos^2x would not that cancel out the cos on the denominator?
what program you use to write your equations?
yes it does, leaving the sin^2x term..
LaTeX - it allows for embedding math equations into questions and responses. You can learn about it here:
https://www.askmehelpdesk.com/math-s...las-50415.html
yeah agreed so for my information in the denominator
the sin^2x/cos^2x was multiply by cos^2x/cos^2x to leave sin^2x which makes it
4/1+sin^2x
then multiply that again by cos^2x/cos^2x
to get 4cos^2x/1+sin^2x+cos^2x
in your example where did the +1 go
Where did the 1+ go on the bottom?
?
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