(sec x+tan x)/(sec x-tan x)=(sinx+1)^2/(cos^2x)
Quote: Originally Posted by crmedina23 (sec x+tan x)/(sec x-tan x)=(sinx+1)^2/(cos^2x) Hint: convert the sec x and tan x functions to their sine and cosine equivalents. Then simplify by mulytiplying numerator and denominator by cosx. Then finally multiply numerator and denominato by (1+sinx).