Three un graduated cylinders one is full with seven liter water, second is full with 13 liter water, third cylinder is empty (ninteen liter water can be filled in third cylinder).
HOW ten, ten liter water can be distributed in second and Third cylinder respectively?
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Thanks

It took me 16 steps of transferring water from cylinder to cylinder without needing to mark the cylinders (cheating). I will use shorthand 7:13:0 to describe the initial condition and => to separate the steps. So the first step is to empty the 7L into the 19L cylinder giving: 0:13:7. The remaining steps are 0:1:19 => 7:1:12 => 0:8:12 => 7:8:5 => 2:13:5 => 2:0:18 => 0:2:18 => 7:2:11 => 0:9:11 => 7:9:4 => 3:13:4 => 3:0:17 => 0:3:17 => 7:3:10 => 0:10:10. Voilà!

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Originally Posted by Chic_Bowdrie

It took me 16 steps of transferring water from cylinder to cylinder without needing to mark the cylinders (cheating). I will use shorthand 7:13:0 to describe the initial condition and => to separate the steps. So the first step is to empty the 7L into the 19L cylinder giving: 0:13:7. The remaining steps are 0:1:19 => 7:1:12 => 0:8:12 => 7:8:5 => 2:13:5 => 2:0:18 => 0:2:18 => 7:2:11 => 0:9:11 => 7:9:4 => 3:13:4 => 3:0:17 => 0:3:17 => 7:3:10 => 0:10:10. Voila!

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Excellent! This is like that scene in the thid "Die Hard" movie where they have to put 3 gallons of water into a 5 gallon container - that riddle was a lot easier than this one.