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-   -   How do I work this type equation? (https://www.askmehelpdesk.com/showthread.php?t=63848)

  • Feb 18, 2007, 07:18 AM
    ymadison1
    How do I work this type equation?
    X divided by 7/8 = 3/5

    X = ?
  • Feb 18, 2007, 07:47 AM
    SBowman
    So its x / (7/8) = 3/5

    x*8/7 = 3/5
    8x / 7 = 3/5
    8x / 7 - 3/5 = 0
    40x / 35 - 21 / 35 = 0
    40x - 21 / 35 = 0

    If you multiply both sides by 35, then you get:
    40x - 21 = 0
    40x = 21
    x = 21 / 40
    x = 0.525

    Let's try and substitute that in:
    .525 / .875 = ?
    .525 / .875 = .6

    So x = .525
    So x = 21 / 40
  • Feb 19, 2007, 08:09 AM
    asterisk_man
    SBowman's final answer is correct but I have two comments:

    First, the following line is wrong:
    40x - 21 / 35 = 0
    It should be
    40x/35 - 21/35=0

    Second, the following method is much simpler:
    x/(7/8)=(3/5)
    multiply both sides by (7/8)
    x=(3/5)*(7/8)
    simplify
    x=21/40
  • Feb 19, 2007, 08:10 AM
    Capuchin
    I agree with asterisk's point, your working made me cringe when I read it SBowman
  • Feb 19, 2007, 10:56 AM
    SBowman
    Ah, found an easier way. Much more effective than my method. :)

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