Ask Me Help Desk - How to solve the system of equations?

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How to solve the system of equations?

$ \left\{ \begin{array}{l l} 28=sqrt{a b}\\ 40=sqrt{(20 a)^2 b^2}\\ \end{array} \right. $

The second equation can be written as:

$ 40 = \sqrt {(20a)^2b^2} = 20ab $

From the first equation you have:

$ 28 = sqrt{ab},\\ 28^2 = ab $

So combining:

$ 40 = 20ab = 28^2\\ 40 = 784 $

It appears that you have two equations that are inconistent. Please check the first two eqautions as written to verify.

Oh, sorry, there should have been "+" between all the terms, but it seems there is a problem with the code.

So, the first equation should have been 28 = sqrt (a + b) and the second one 40 = sqrt ( (20 + a)^ + b^2)

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