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-   -   Help with trigonometric identity (https://www.askmehelpdesk.com/showthread.php?t=635892)

  • Feb 14, 2012, 12:56 AM
    superracer21x
    Help with trigonometric identity
    sin2x/sinx - cos2x/cosx = secx
  • Feb 14, 2012, 06:37 AM
    ebaines
    If you apply the identities sin(2x) = 2 sin(x)cos(x) and cos(2x) = 2cos(x) -1 it world right out.

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