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  • Jan 11, 2012, 01:43 AM
    ranij
    Math Answers Ratios
    A certain quantity of 40% solution is replaced by a 25% solution sch that the new concentration ratio is 35% What is the ration of solution that was replaced to the ratio of the solution that was not replaced?
  • Jan 12, 2012, 06:45 AM
    ebaines
    You need to set up an equation that represents the word problem:

    "A certain quantity of 40% solution": if we let Q = the quantity of solution, then the amount of "stuff" in this solution is 0.4Q.

    "is replaced by a 25% solution": hence an amount x of the solution is removed and new 25% solution replaces it, so the total amount of "stuff" in solution is now: 0.4(Q-x)+0.25x

    "such that the new concentration ratio is 35%": the total amount of liquid is still Q, but at 35% concentration, so:
    0.4(Q-x)+0.25x = 0.35Q

    Now you can solve for x, and find the ratio of x/Q.

    Post back with your answer and we'll check it for you.

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