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-   -   Can you solve this problem for me? (https://www.askmehelpdesk.com/showthread.php?t=620007)

  • Dec 15, 2011, 09:57 PM
    laura_
    Can you solve this problem for me?
    If a high-speed industrial drill with the diameter of 42 in and a torque of 15 lb-ft develops a power of 2.8 hp. a) what is the speed of the drill in RPM? b) what is the force?
  • Dec 16, 2011, 06:56 AM
    ebaines
    I won't solve it for you, but I'll show you how to do it:

    a) Power = torque times rotational speed. You know the power and torque, so solve for rotational speed. You'll have to use the conversion factor 1 HP = 550 ft-lb/s.

    b) Torque = force times radius. Solve for force.
  • Sep 16, 2014, 12:37 PM
    bhamman
    Help me solve this problem, I am totally lost
    -5c+9c =-20

    -5c+9c=-20
  • Sep 16, 2014, 12:43 PM
    ebaines
    To get started, do you know what -5+9 equals? Hence, what does -5c+9c equal?
  • Sep 16, 2014, 12:44 PM
    CravenMorhead
    Um think about it this way.

    First thing is to look at the terms 5c and 9c. Those equate to (c+c+c+c+c) and (c+c+c+c+c+c+c+c+c). The 5 and the 9 are the number of c you have. So you can add the numbers in front of the variable. Then you have a number of c that will equal -20. So if you divide each side by the number you c you have after you've added the two numbers together you will get your answer.

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