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-   -   Question about Calculus----Graph of a Function.. (https://www.askmehelpdesk.com/showthread.php?t=617022)

  • Dec 5, 2011, 06:07 AM
    Wikkibahi
    1 Attachment(s)
    Question about Calculus----Graph of a Function..
    I attach the following Math Pdf File, Please Open it and solve my Problem as soon as possible.
    Thanks a lot for this.
  • Dec 5, 2011, 06:22 AM
    ebaines
    Theyt want you to graph for in the domain [-3,3].


    Start by calculating the value for f(x) for each of several key values of x. For example, at one end of the domain you have x = -3, so determine f(-3):


    (Note that the absolute value of -3 is 3.) Now continue for other key points - I suggest trying x = -1, x=0, x = 1, x=2 and x=3. You should find that the graph is basically a bent line. Post back with what you get and we'll check it for you.
  • Dec 5, 2011, 09:00 AM
    Aurora2000
    If they want , see ebaines's comment.

    If they want (which produces a graph more like "saw tooth"), you should use the definition of : . It is also called "integer part" function (this because you simply remove the decimal part for positive numbers - for negative numbers it is a little bit different, for negative integers [] acts like identity, while for negative non integers you remove the decimal part and subtract 1): e.g. [3.554]=3, [1.473]=1, [0,833]=0, [e]=2, etc. but [-3.2]=-4, [-1]=-1, [-e]=-3 etc.

    So , find the rest.

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