Maximize (A 3)(B-2) if A B=40
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Maximize (A 3)(B-2) if A B=40
Substitution:
Now differentiate the expression, and impose it equal to 0:
which leads to B=23. Second derivative is negative, which means B=23 is a local maximum. Substitute B=23 in the original expression.
Oops, there is a typo with B-3 instead of B-2:
using the same argument you have B=45/2 which maximizes the expression.
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