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-   -   Pre-cal question. (https://www.askmehelpdesk.com/showthread.php?t=613697)

  • Nov 20, 2011, 03:59 PM
    K_T.T.
    pre-cal question.
    Please help me solve this, I have tried several ways and still doesn't come out corectly.

    Prove the following:

    cos^3x-sin^3x/ cosx-sinx=1 sin^2x.
  • Nov 20, 2011, 04:02 PM
    K_T.T.
    Pre-calculus
    Please help me solve this, I have tried several ways and still doesn't come out correctly.

    Prove the following:

    cos^3x-sin^3x/ cosx-sinx=1 sin^2x.
  • Nov 20, 2011, 04:04 PM
    Fr_Chuck
    Show us what you tired, we do not "do" the work for you, but will suggest where you are making your errors.
  • Nov 20, 2011, 04:10 PM
    K_T.T.
    this is how far I got to,

    cosx-sinx(cos^2x+sinxcosx+sin^2x)/cosx-sinx

    since the top and bottom cancel out, I got

    cos^2x+sinxcosx+sin^2x

    I reduced further to

    1+sinxcosx

    this is where I got stuck at because on the other side of the equation equals to 1+sin^2x
  • Nov 21, 2011, 03:10 AM
    Aurora2000
    What you are doing is correct, but are you sure the request is

    ?

    Try : ,
    then the left side reads
    which is an irrational number
    while right side is 5/4.


  • Nov 21, 2011, 03:13 AM
    Aurora2000
    Oops, some problem with mimeTex (it does not recognize the command \ dfrac as LaTeX does)

    What you are doing is correct, but are you sure the request is

    ?

    Try , you will get an irrational value on the left side, and 5/4 on the right side.

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