^ means power of
2nd question - numbers should be subscripted
Ï€ means pi


v^2 = u^2 2as for v

p1 A1 v1 = p2 A2 v2 for A1

v = πr^2h for r

x-a x-b =1 for x

b c


Please provide working out as well as answers so I can learn,thanks

sorry the c in the third queston should be below x-b

Also an addition sign should be between x-a and a-b, and also before 2as in the first question

for v

Take the square root on both sides.

for A1

Divide both sides by

for r

First divide both sides by , then take the square root on both sides.

for x

1. Multiply both sides by the least common multiple of the fractions.
2. Expand and simplify the brackets which will be formed.
3. Add/Subtract anything on both sides so that terms in x only remain on the left.
4. Factor out x.
5. Divide by the coefficient of x.

Can you post what you get? :)

My first answer is 1st step √v^2 = √u^2 + 2as
2nd step V = u^2 + √2as

Here is my first answer to the 1st question 1st step (square rt v^2) = (square rt u^2) + 2as The brackets make it easier to show what I am square rooting 2nd step V = u^2 + (square rt 2as)

2nd question answer 1st step p1A1v1 = p2A2v2
p1v1 p1v1

2nd step A1 = p2A2v2
p1v1

The p1v1 p1v1 and p1v1 should be directly below the lines sorry!

3rd question 1st v = πr^2h
πh πh

2nd v = r^2
Ï€h

3rd (square rt v) = r^2
Ï€h

�€ means pi

I couldn't work out the last one, couuld you please verify my answers and show me how to get the last question, thanks josh.



















�€h

* π means pi

Quote:

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Originally Posted by Josh2345

My first answer is 1st step √v^2 = √u^2 + 2as
2nd step V = u^2 + √2as

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You mean this?



No, that's wrong. It should be this:



When you do something on one side, the same thing must happen on the whole other side.

2. Good

3. Same thing here. It should be:



4.

First multiply by the least common multiple of the denominators.



The L.C.M is because, hence:







Can you expand here?

Thanks unknown, I will learn from this.

I have expanded the last! A = -1b + bc-1x + -1b2c-1 + x

Um.. I'm not sure where you got that...



Here is what you get when you expand.

Now, bringing all the x and terms not in x on different sides:





Can you factor x here on the left and then divide both sides by (c + b)?

Will I need to rearrange the equation in the form "(quadratic) = 0"?

is the answer to the first step x^2=cb+bc+ca+b^2

No no no. How do you factorise cx + bx?

Just like that:

2x + 3x = x(2 + 3)

Ok x(C+B) Now do I divide both sides by (c+b)?

So the final answer is x=bc+ca+b^2
(c+b)