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Quadratic Problem

One side of a rectangle is 1m less than the length of the diagonal. If the area of the rectangle is 60m squared , what are its dimension.

Assign variables.

Let l be the length of the rectangle.
Let w be the width of the rectangle.

The diagonal is obtained through the Pythagoras' Theorem,

$Diagonal = \sqrt{l^2 + w^2}$

Let the length be less than the diagonal

$\sqrt{l^2 + w^2} - 1 = l$

The area is $lw = 60$

Can you take it from here?

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