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-   -   Incline speed (https://www.askmehelpdesk.com/showthread.php?t=60114)

  • Feb 4, 2007, 05:02 PM
    tnhoots
    incline speed
    1. The problem statement, all variables and given/known data

    Two objects are connected by a light string that passes over a frictionless pulley, as in Figure P5.26. The incline is frictionless, m1 = 2.00 kg, m2 = 6.00 kg, and = 50.0°.

    (?) Find the speed of each object 2.00 s after being released from rest.
    m/s


    2. Relevant equations

    I already found the acceleration to be 3.18 m/s2 using the equation:
    a=(m2)(g)(sin50.0)-(m1)(g) / m1 + m2

    I already found the tension in the string to be 25.9 using the equation:
    T=(m1)(m2)(g)(sin50.0+1) / (m1+m2)



    3. The attempt at a solution

    I cannot figure out how to find the speed. I'm not even sure what equation to use for this type of problem. I was thinking S=mass/acceleration. But that equation doesn't take into account the friction.
  • Feb 4, 2007, 07:38 PM
    worthbeads
    Quote:
    Originally Posted by tnhoots
    1. The problem statement, all variables and given/known data

    Two objects are connected by a light string that passes over a frictionless pulley, as in Figure P5.26. The incline is frictionless, m1 = 2.00 kg, m2 = 6.00 kg, and = 50.0°.


    I cannot figure out how to find the speed. I'm not even sure what equation to use for this type of problem. I was thinking S=mass/acceleration. But that equation doesn't take into account the friction.
    You said there was no friction.
  • Feb 4, 2007, 07:45 PM
    tnhoots
    Oops just kidding. I'm still unsure of how to find the speed taking into account, the mass, acceleration and time. Is there a formula for that?
  • Feb 4, 2007, 07:50 PM
    worthbeads
    Yes, I am pretty sure, but I probably can't give you a correct answer. I'll leave that for someone else.
  • Feb 5, 2007, 01:41 AM
    Capuchin
    The diagram would be useful.
  • Feb 5, 2007, 09:07 AM
    tnhoots
    I'm not looking for the correct answer. I would never ask you to give me the answer. I am willing to do the work to find the answer. I just don't know where to begin.
  • Feb 5, 2007, 10:33 AM
    tnhoots
    I'm thinking that I would use the equation:
    V=Vo + at
    V=0 + (3.18)(2)
    V= 6.36 seconds

    Am I on the right path?
  • Feb 5, 2007, 10:42 AM
    Capuchin
    you do need to use suvat equations, but you have to include the tension

    can you scan the figure?

    Oh you already have acceleration, then yes you are correct, v = u+at

    Quote:
    V= 6.36 seconds
    units... :)

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