How do I calculate if I have 8 cans of soda: 2 colas, 5 orange, 1 cherry. 2 cans are selected at random without replacement. What is probability that at least one can is orange

When you have questions with 'at least', you can do 1 - P(none).

Here, the P(none) will be P(no orange cans are picked).

What is the probability that out of the 2 cans randomly picked, none are orange?

Then, subtract that value from one.

Can you post your answer? :)

Out of 8 cans 3/8 are non-orange. I think that probability of 2 cans not being orange is 3/8 X 2/7
or 6/56. Subtracted from one is 50/56, or 25/28. That is the answer. THANK YOU!

Indeed! Well done myrmiller! :)