so there's a triangle,
A= 45 degrees
B= ?
C= ?
b=5
a=?
c= 3√2
So for this triangle, since it's side angle side, I decided to use the law of cosines, and since we need to find side a, I used the formula,
a^2=b^2+c^2-2bcCos(A)
So I did √(5^2+3√(2)^2-2(5)(3√(2))Cos(45 degrees)
But I'm not getting the answer, which is √13
What am I doing wrong?