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5=log(1000+Q) calculate Q

5=log(1000+Q) calculate Q?

Apply the definition of the logarithm: If

$\log_a b = c$

then

$a^c = b$

For this problem you have (assuming the log is base 10):

$<br /> 5 = \log_{10} (1000+Q)<br />$

so

$10^5 = 1000+Q<br />$

I'm sure you can take it from here.

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