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-   -   Pre cal (https://www.askmehelpdesk.com/showthread.php?t=579008)

  • May 29, 2011, 11:18 PM
    saadsaad
    pre cal
    {tan (pi / 2 - x ) sec x } / 1-csc^2 x
  • May 30, 2011, 09:38 AM
    RickJ

    What is your question?
  • May 31, 2011, 06:51 AM
    ebaines

    saadsaad - if your question is how to simplify this, try replacing the tan, sec, and csc functions with their sine and cosine primitives. And recall that sin(pi/2-x) = cos(x), and cos(pi/2 - x) = sin(x).

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