Ask Me Help Desk

Ask Me Help Desk (https://www.askmehelpdesk.com/forum.php)
-   Physics (https://www.askmehelpdesk.com/forumdisplay.php?f=258)
-   -   Please solve (https://www.askmehelpdesk.com/showthread.php?t=574586)

  • May 4, 2011, 09:11 PM
    divyasharma
    please solve
    a particle is projected from a horizontal plane to pass over to the objects at height h and k and a slant distance d apart. What is the least possible speed of projection?




    ans:(g(h+k+d))^1/2
  • May 4, 2011, 09:15 PM
    divyasharma
    solve :
    a particle projected at an angle a with the horizontal from the foot of an inclined plane making an angle b with horizontal. Show:
    cotb=2tan(a-b)
  • May 4, 2011, 09:19 PM
    divyasharma
    Can anyone help?
    When the range of a projectile on an inclined plane is maximum then
    1.the focus of the path is on the plane
    2.the focus of the path is below the plane
    3.the focus of the path is above the plane
    4.the focus of the path is at any place

    Please give detailed answer
  • May 4, 2011, 09:36 PM
    divyasharma
    Can someone solve
    A girl going eastwards with a velocity of 4km/hr, find that the wind appears to blow directly from north/. She doubles her speed and the wind appears to blow from north east. The actual velocity of wind is? (direction and magnitude)
  • May 4, 2011, 09:41 PM
    divyasharma
    Newtons laws of motion
    A heavy block of mass m is supported by a cord C attached to the ceiling , and another cord D is attached to the bottom of the given block . If a sudden jerk is given to D, then
    1. cord C breaks
    2.cord D breaks
    3. none breaks
  • May 4, 2011, 09:46 PM
    divyasharma
    laws of motion
    a particle of mass m is moving under the variable force f. if magnitude of f is constant, then the possible path of the particle can never be:
    1. rectilinear
    2.circular
    3.parabolic
    4.elliptical

    do explain
  • May 4, 2011, 09:53 PM
    divyasharma
    newtons law of motion
    a particle of mass m move son the x axis as follows. It starts from rest at t=0 from thr point x=0, and comes to rest at t=1 at the point x=1. no other information is available about its motion at intermediate time . If a denotes instantaneous acceleration of the particle
    prove that
    |a|be>=4 at point or some points in its path
  • May 4, 2011, 10:23 PM
    divyasharma
    Can someone solve
    A particle is found to be at rest when seen from frame S1 and moving with a constant velocity when seen from another frame S2.
    Mark the possible points from the following:
    1. both frame sare inertial
    2. both frames are noninertial.
    3. s1 is non inertial and s2 is inertial
    4.both a and b are correct
  • May 4, 2011, 10:28 PM
    Curlyben
    Thank you for taking the time to copy your homework to AMHD.
    Please refer to this announcement: CLICK HERE !!
  • May 4, 2011, 10:54 PM
    divyasharma
    Work energy and power
    An insect is crawling up a fixed hemispherical bowl of radius R.the coefficient of friction between insect and bowl is 1/3. the insect can only crawl up to a height
    1. 60% of R
    2.10% of R
    3.5% of R
    4.100% of R
  • May 7, 2011, 11:38 AM
    jcaron2
    divyasharma, Curlyben was right to post that announcement. We really are here to HELP you, not to completely do your homework for you. The red "No" feedback should be reserved for answers which are factually incorrect, not just because it wasn't the answer you were looking for.

    Now, having said that, I'll be happy to give you some assistance on this problem. Unfortunately, however, it's not very clear what you mean. I'm assuming there's a diagram to go with the problem? Can you please explain the drawing a little more clearly or, if possible, scan it? I'm not sure what you mean when you say "and a slant distance d apart".


  • May 8, 2011, 01:55 AM
    Unknown008

    Someone should merge those merged threads in a single post. There are 9 questions posted, but only the first is visible to users using Go...

  • All times are GMT -7. The time now is 09:49 AM.