5x-8y = 25
-x+4y = -7
This is what I did:
5x-8y =25
-2x+8y = -14
_____________
x = 11/3??
Is this right? What are the next steps and how would you write this? :confused:
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5x-8y = 25
-x+4y = -7
This is what I did:
5x-8y =25
-2x+8y = -14
_____________
x = 11/3??
Is this right? What are the next steps and how would you write this? :confused:
yes 11/3 is correct for x value. Now you must sub this value into one of the equations to get the y value.
Ok, thanks. But now if I plug into the first equation it looks like this:
5(11/3) - 8y = 25
What do I do now?
Multiply out the brackets and solve...
Just solve for y in that new equation the same way you solved for x before.
Not exactly the same. Capuchin was correct by saying just multiply out the brackets and solve. Post your answer and we'll tell you if its rightQuote:
Originally Posted by Nosnosna
I got -10/12? Is the answer 11/3, -10/12
Yes but remember that -10/12 reduces to -5/6
Good Job!
Great.. Thanks for all your help..
if the perimeter of the rectangle is t units and the area is 2t+5 squre units,what is the value of x?
Can anyone help me with my this que...
if the perimeter of the rectangle is t units and the area is 2t+5 squre units,what is the value of x?
You should post your question under your own new thread. Your question has nothing to do with elimination, and the thread is also a year and a half old.
2x-3y=-11
3x+4y=16
I got the answer is x= 3/6
Sigh COOLIOZ, have you read the previous posts? Especially that of morgaine?
DANNYSENDIN, your answer is wrong. X = 4/17.Quote:
Originally Posted by morgaine
Yeah, thanks folks for wasting my time reading through this entire thread yet again.
Sigh.
and substitute 11 in equation (1)
5x-8y=25
5(11)-8y=25
-8y=25-55
-8y=-30
-8
y = 3.75
People, read the previous posts please. Problem solved already.
THREAD CLOSED
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