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  • Apr 28, 2011, 09:14 PM
    KeeKee77
    Electric Fields and Forces
    If a negative test charge with excess of 4.8 x 10^3 electrons feels a force of 7.75N to the left when placed to the left of a larger charged field. Calculate the electric field intensity and its direction.
  • Apr 29, 2011, 09:23 AM
    Unknown008

    1. use

    F is the force, E is the electric field strength and q is the charge of the test charge.

    2. For the direction, you tell us what you think is right, and why you feel so :)

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