In the picture you can see Three different tanks contain Three different gases.
The temperature are equal to 25 Degrees Celsius
In all the Three tanks, and it not changing.

I asked to calculate the kinetic energy of the Three different gases.
So I thought to use this formula:3/2*RT this formula is for ideal gas but how can I know if what I got here is an ideal gas ?

Or maybe I need to use in another formula?
Thanks.
http://p1cture.me/images/05404830057468198676.jpg

Well, in the lessons I had, I was told to assume that the gases I worked with to have ideal behaviour.

OK so if I assume that this gases are ideal do I correct in my formula ?
Thank you.

Well... you used the wrong constant.

well look here :http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/kintem.html I think I correct in my formula no ? :)
btw: N = number of molecules is not given in my question info, also n. so I can't use in your formula yes?
thank you again.

Your site is correct, but what you typed is not :p

See in my post, all the equivalents of E, you'll see the one you can use :)

But still, you don't need n, or N, since you know N_A ;)

well so I can use this formula:E=3/2kT (kinetic energy of gas molecule) k=Boltzmann constant T=Kelvin temperature.
so I got the correct formula now? Lol.

sorry for making it to look so hard :) thanks.

Yes, now, this is correct :)

Hi.
Thank you very much for help but if you says that is will be correct to use this formula E=3/2kT and we know that k and T in this case are equal in all the 3 gases so I get that the kinetic energy of each gas here are equal ?

Is it possible ?

Lol never mind I did it :)

Thanks.

Yes that's right. As long as T is constant, the KE of the particles will be constant.

Well, the average KE that is.

Remember that KE of molecules of gas is only affected by their temperature.

OK so this what I got:3/2*1.38*10^-23J*K*298K=6.1686^-21 so 6.1686^-21is the average KE of the 3 gases ?

Yes, I get that too :)

YeA thanks you for your patience :)