2. Given f(x) = k(2+x), find the value of k if f^-1 (-2) = -3
3. Consider the following function:
f(x) = -2 all square (-x + 4) -3 find the equation of the inverse function
One you graph f(x) and its inverse on a grid
find Df, D f-1, Rf, R f-1
![]() |
2. Given f(x) = k(2+x), find the value of k if f^-1 (-2) = -3
3. Consider the following function:
f(x) = -2 all square (-x + 4) -3 find the equation of the inverse function
One you graph f(x) and its inverse on a grid
find Df, D f-1, Rf, R f-1
I will try to decipher.
Replace f(x) with y:Quote:
2.![]()
swap x and y:
.
Solve for y.
Then, sub in x=-2, set the equation equal to -3 and solve for k.
Replace f(x) with y:Quote:
3. Find the inverse of![]()
swap x and y:
Now, solve for y.
They are easy to graph with a calculator or graphing utility.
Here is a link to a wonderful FREE graphing utility:
www.padowan.dk
I do not know what Df, Rf, and so forth means.
Galactus, I need to tell you something
2. Consider the following function f(x) = -2 sqrt (-x + 4) - 3
a) find the equation of the inverse function and graph f(x) and its inverse on a grid
b) find Df
Find D f^-1
Rf
R f^-1
Those are domain and range can you please show me the full work I've been having a lot of trouble on this thanks
Can you draw the graph of f(x) ?
The domain is the horizontal interval of a function.
Let's say that I hadfor
Then,for
When you draw f and f^-1, you'll see that:
The domain of f will lie between 0 and infinity. That is looking on the horizontal axis, f starts at zero and never ends.
Similarly, the domain of f^-1 will be between 0 and infinity.
The range of f is the vertical interval. Looking on the y axis, f starts at 0 and rises to infinity. The range is thus 0 to infinity. Same thing for f^-1.
Now, can you deduce the range and domain of the functions in your problem?
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