Ask Me Help Desk - Log5 1=log5 x-log5 8

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log5 1=log5 x-log5 8

I assume that is base 5?

$log_{5}(1)=log_{5}(x)-log_{5}(8)$ ?

The left side of the equation is obviously 0. Because log(1)=0

Therefore, what must x be?

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