2. Consider the following reaction for which Kp = 0.0752 at 480.0 °C.
2 Cl2 (g) + 2 H2O (g) goes to 4 HCl (g) + O2 (g)
a) Calculate Kp for: 2 HCl (g) + ½ O2 (g) goes to Cl2 (g) + H2O (g)
b) Calculate Kp for: 8 Cl2 (g) + 8 H2O (g) goes to 16 HCl (g) + 4 O2 (g)




Kp = 0.0752 at 480.0 °C. 2Cl2(g) + 2H2O(g) goes to 4HCl(g) + O2(g)

Consider the following reaction for which Kp = 0.0752 at 480.0 °C.
2 Cl2 (g) + 2 H2O (g) goes to 4 HCl (g) + O2 (g)
Calculate Kc.

You have to know two things:

1. If a reaction of the type:



Then, the equation for Kp is:



And the reverse reaction is:





In other words

2. K constants are always always constant, except when temperature changes.

Also,