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-   -   How do you answer 28a^5/7a^3 (https://www.askmehelpdesk.com/showthread.php?t=558619)

  • Feb 28, 2011, 04:24 PM
    miamiamia
    how do you answer 28a^5/7a^3
  • Feb 28, 2011, 04:59 PM
    freshangel15
    You divide the coefficients and subtract the powers. You should get 4a^2
  • Feb 28, 2011, 08:11 PM
    jcaron2
    Comment on freshangel15's post
    Exactly.
  • Mar 10, 2011, 12:02 PM
    RPVega
    I'm assuming you mean (28*a^5)/(7*a^3)? If that's the case, here's the
    answer: 4*(a^2).

    Explanation:

    First, divide 28 by 7, to get 4 in the numerator. Next, divide a^5 by a^3.
    To do this, subtract 5 from 3 to get 2. Remember, 1/(a^3)= a^(-3). Then you
    have (a^5)*(a^-3) in the numerator. To evaluate (a^5)*(a^-3), simply ADD the
    exponents of the base,a, which is a^(5-3)= a^2. Since 28/7=4, the answer is
    4*(a^2). I know it's confusing... This problem involves a mastery of the
    properties of exponents. Good luck!

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