Kinetic energy and Potential energy
Vehicle with a weight 2.8 ton Slowing from 100 km/h to 50Kkm/h how much energy can was generate from this Slowing.
(if we Ignore form friction )
and to which Height this energy was can Climb up the Vehicle Up the hill
I convert the ton to Kg is gave me 2800Kg and the km/h to meter per second
I tried to use with the formula Ek=1/2mv^2 and U=mgh but I am not understand how to solve it.
so I need help.
thanks.
Comment on Unknown008's post
Yes I know, this why I am not sure.
Thank you.
Comment on Unknown008's post
well 4.0*10^3 Kj
but I am not know how to find the way for this answer
Comment on Unknown008's post
OK so to find h I need to do 810185 J/2800 kg * 9.81 m/s^2 = h?
I just divide the both side of the equation in 2800 kg * 9.81 m/s^2
if I correct is not gave me 29.5 m
thank you :)
Comment on Unknown008's post
Sorry but I want to make sure I understood your English (which is quite good considering it's not your primary language). You did get 29.5 m? Or you did not?
You should put some parentheses in your equation to find h: h=810185 / (2800*9.81)= 29.5. Otherwise, as you wrote it, it's the same as (810185/2800)*9.81, which is incorrect.
Comment on Unknown008's post
I felt a lot more confident about it after you, too, said you thought 4000 kJ was incorrect. :)
Comment on Unknown008's post
No no I sorry I did some mistake in my calculation and yes I also get 29.5m
Thank you so much for helping also to you unknown008 :)