If tanA = -4/3 and cosB = 15/17, where A lies in the 2nd quadrant, and B lies in the 4th quadrant.
Find the exact value of tan(A+B)
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If tanA = -4/3 and cosB = 15/17, where A lies in the 2nd quadrant, and B lies in the 4th quadrant.
Find the exact value of tan(A+B)
You know how to expand the tan(A+B) using the compound angles formula? I suggest you do so.
Then, to get tanB, you'll have to make a quick sketch of a right angled triangle, with angle B, adjacent side 15 and hypotenuse 17.
Work out the opposite side using Pythagoras' Theorem.
Then, find tan B which is opp/adj
Replace the values of tanA and tanB in your compound angle formula.
Post what you get! :)
Yea I did that, I was like "ARGGHHH HOW THE HELL DO YOU GET TANB???" I discovered shortly after I posted...
I ended up with 36/77... Idk if that's right.
*-36/77
Okay, I get:
And since B is in the 4th quadrant, tan B is negative, hence:
Then;
You can confirm by using your calculator.
which is 126.9 in the 2nd quadrant
which is 331.9 degrees in the 4th quadrant
Total, gives tan(126.9 + 331.9) = -6.45 which is about -84/13
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