how do you factor m^6-27n^3?
or m^6+27n^3?

First notice that 27 = 3^3. So these equations can be rewritten as the difference of cubes for the first one, and the sum of cubes for the second:



and



The difference of cubes can be factored like this:



and the sum of cubes can be factored like this:



Hope this helps.