Ask Me Help Desk - Tan(x) sec(x)-1)/(tan(x)-sec(x) 1)=tan(x) sec(x)

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tan(x) sec(x)-1)/(tan(x)-sec(x) 1)=tan(x) sec(x)

Please help me verify this!

Please retype the question, and this time please make sure that the parentheses match up. It seems like you mean this:

$<br /> \frac {\tan (x) \sec (x) -1}{\tan (x)-\sec (x)+1} = \tan (x) \sec (x)<br />$

But this isn't correct. Please clarify.

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