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-   -   How do I figure out what conic section this equation makes? (https://www.askmehelpdesk.com/showthread.php?t=542297)

  • Jan 9, 2011, 03:26 PM
    maramfaith24
    How do I figure out what conic section this equation makes?
    I'm not looking for answer, just the step to finish the equation and figure out which conic section it forms?

    Here's the equation: x^2=y^2+9.

    I think I start by putting the equation into y=mx+b form, so it can be graph on a graphing calculator.

    But I can't figure out how it's going to look in the end, can you help?
  • Jan 9, 2011, 03:44 PM
    galactus

    How could you write it in y=mx+b form? y=mx+b is the slope intercept form of a line.

    This has nothing to do with a line.

    I think you are just referring to solving it for y so you can graph it.

    Yes, you can do that.

    To solve it without graphing, rewrite it as:



    Divide by 9:



    This is a hyperbola with vertices at (-3,0) and (3,0)
  • Jan 9, 2011, 04:35 PM
    maramfaith24
    Comment on galactus's post
    So would re-write be the easier way of the two? I'm sorry, I am just really conused. I'm an online student, so if I don't understand something.. This website is normally where I come.
  • Jan 9, 2011, 04:49 PM
    maramfaith24
    Comment on galactus's post
    The way my teacher wants my to do it, is to first solve or y.
  • Jan 10, 2011, 05:42 AM
    galactus

    I already solved it for y.

    Graph that in your calculator.

    Don't forget the positive and negative or you'll just get one side.

    Graph and

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